Speaker Crossover Calculator estimates passive two-way crossover component values for a woofer low-pass branch and tweeter high-pass branch using nominal driver impedances.
Calculate passive crossover components
Speaker Crossover Calculator formulas
Second-order Butterworth: L = 0.2251Z ÷ f, C = 0.1125 ÷ (fZ)
Second-order Linkwitz–Riley: L = 0.3183Z ÷ f, C = 0.1592 ÷ (fZ)
Inductance is calculated in henries, capacitance in farads, frequency in hertz and impedance in ohms. For second-order networks, the inductor and capacitor exchange series and shunt positions between the low-pass and high-pass branches.
Worked example
At 3,000 Hz with 8 Ω woofer and tweeter impedances, a second-order Butterworth starting network uses approximately 0.600 mH and 4.688 µF in the woofer branch. The tweeter branch uses approximately 4.688 µF and 0.600 mH. Nearby standard values may be selected, but measurements determine whether those substitutions improve the acoustic response.
Designing a practical speaker crossover
A passive crossover separates an amplifier signal into frequency ranges for different drivers. The low-pass branch reduces high-frequency energy reaching the woofer, while the high-pass branch protects the tweeter from excessive low-frequency energy. Electrical slope describes the ideal network, but the final acoustic slope also includes each driver’s natural response.
Nominal impedance is an approximation
A driver labeled 8 Ω does not remain at 8 Ω across frequency. Its impedance curve contains a resonance peak and usually rises at high frequencies because of voice-coil inductance. The Speaker Crossover Calculator assumes a resistive value at the crossover point. For better accuracy, use measured impedance data or an impedance-compensation network designed for the actual driver.
Butterworth and Linkwitz–Riley alignments
A first-order Butterworth filter uses one reactive component per driver and has a gentle 6 dB-per-octave electrical slope. A second-order Butterworth network is steeper and ideally has a Q of about 0.707. A second-order Linkwitz–Riley response uses a Q of 0.5 and is often selected when designers want the acoustic outputs to sum predictably after accounting for polarity and driver behavior.
Polarity and acoustic phase
Second-order electrical branches have a relative phase relationship that commonly leads designers to begin testing with one driver reversed. This is guidance, not a universal wiring rule. Driver acoustic centers, natural roll-off, enclosure geometry and listening axis affect the measured phase. Verify the summed response around the crossover frequency.
Component quality and ratings
Use capacitors with appropriate voltage and loss characteristics and inductors with suitable wire gauge, current capability and low DC resistance. Inductor resistance changes the woofer level and filter Q. Capacitor tolerance changes crossover frequency. High-power systems require components that tolerate expected RMS and peak conditions without overheating.
Measurement is essential
The Speaker Crossover Calculator provides textbook electrical values, not a finished loudspeaker design. Measure frequency response, impedance and distortion in the intended enclosure. Adjust for driver sensitivity using attenuation where needed and check tweeter power handling below the crossover point. Simulation based on manufacturer FRD and ZMA data is much more reliable than nominal impedance alone.
Review established passive-filter theory and measurement practice in the Linkwitz filter design reference. Always confirm manufacturer specifications and protect the amplifier from unsafe impedance.
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Frequently asked questions
Can I use nominal speaker impedance?
Yes for an initial estimate, but measured impedance near the intended crossover frequency produces a more realistic design.
Should the tweeter polarity be reversed?
Second-order networks commonly begin with one driver reversed, but the correct final polarity must be confirmed by acoustic measurement.
Can this calculator design a three-way crossover?
No. This page calculates a basic two-way network. Three-way systems require interacting low-pass, band-pass and high-pass sections.
Why do real results differ from the calculation?
Drivers are not resistors. Their impedance, frequency response, acoustic offset, enclosure and component losses alter the final response.